sq5 dante card price

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  • #119507
    Profile photo of QuDrewQuDrew
    Participant

    Can someone explain to me why the sq5 dante card is roughly twice as much as a comparable yamaha TF series dante card?

    thanks,
    Andrew

    #119511
    Profile photo of nottooloudnottooloud
    Participant

    It’s also half the price of the D-Live/Avantis 64 channel Dante card. There are lots of reasons. Different channel counts. Technology changes. Some manufacturers make their own chips.

    #119518
    Profile photo of TobiTobi
    Participant

    Its twice as good 🙂

    #119659
    Profile photo of QuDrewQuDrew
    Participant

    this is not a serious forum..

    #119661
    Profile photo of TobiTobi
    Participant

    The question was Strange.

    #119664
    Profile photo of Søren SteinmetzSøren Steinmetz
    Participant

    Big part of the reason could be:

    1: NY64-D is strictly 48khz vs the A&H card 48K + 96K

    2: The A&H has src (Sample Rate Converter) allowing you to run 48K on the Dante network, while still run 96K internal in the console (wivh btw the console always do, regardless og external connections)

    These two points require a higher standard of components after all.

    #119675
    Profile photo of BrianBrian
    Participant

    this is not a serious forum..

    I disagree. The first response to your question was accurate. The A&H SQ Dante card is twice as expensive as the Yamaha NY64-D card because in part, it is twice as powerful. Normal Dante chips will half the I/O count when you increase the clock speed from 48k to 96k. The Allen & Heath card does not do this. You can get the full 64 I/O channel count even running at 96k. The Yamaha card cannot do this, and most other non A&H Dante products can’t either. This is because A&H has designed their Dante cards themselves and don’t use the standard Audinate chips in their products, ensuring the get full channel I/O capabilities even running at 96k.

    Is that serious enough for you? 😉

    #119684
    Profile photo of QuDrewQuDrew
    Participant

    thank you. I appreciate these answers

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